Re: Making Python Script Exit Completely with One Ctrl+C

From: Hongyi Zhao via curl-users <curl-users_at_lists.haxx.se>
Date: Sun, 10 Dec 2023 12:35:16 +0800

On Sun, Dec 10, 2023 at 10:58 AM Dan Fandrich via curl-users
<curl-users_at_lists.haxx.se> wrote:
>
> On Sat, Dec 09, 2023 at 01:51:13PM +0800, Hongyi Zhao via curl-users wrote:
> > Now, I try to compare the manually computed average speed and the one
> > given by pycurl in the attached script, but the latter always is 0:
> [...]
> > try:
> > c.perform()
> > py_speed = c.getinfo(pycurl.SPEED_DOWNLOAD) / 1024
> > except pycurl.error as e:
> > pass
> > finally:
> > c.close()
>
> Are you sure c.perform() isn't raising an exception? That would leave py_speed
> as 0, as you are observing. Hiding exceptions like this can cause no end of
> problems when things go wrong.

The attached script does the trick:

(datasci) werner_at_X10DAi:~/Desktop$ python rev-3.6.py
Testing Proxy: SG_ssr_futeapbquf5m.nodelist.club_1453_018d83c677e05e71f172014fc3f45e39
Current Speed: 21.04 kB/s
Current Speed: 3726.05 kB/s
Error occurred while performing curl: (28, 'Operation timed out after
5000 milliseconds with 29650632 out of 1073741824 bytes received')
PycURL Speed: 5791.21 kB/s
Average Speed: 5790.76 kB/s
Testing Proxy: HK_ssr_wo8o8npg4fny.nodelist.club_1303_b5bf85111d0f51c517ec7302d3f33ce1
Current Speed: 828.35 kB/s
Current Speed: 5367.13 kB/s
Error occurred while performing curl: (28, 'Operation timed out after
5000 milliseconds with 33954720 out of 1073741824 bytes received')
PycURL Speed: 6631.92 kB/s
Average Speed: 6631.49 kB/s
Testing Proxy: SG_ssr_futeapbquf5m.nodelist.club_1354_ddfba110eddfdb7037f389e9b5917477
^CKeyboardInterrupt at line 72

But I still cannot figure out how to achieve the same purpose with the
following methods:

1. Using the following method suggested by you:

You'll probably have to block SIGINT before calling calling into pycurl, then
unblocking in the progress callback to check it, e.g.

...
signal.pthread_sigmask(signal.SIG_BLOCK, [signal.SIGINT])
c.perform()
signal.pthread_sigmask(signal.SIG_UNBLOCK, [signal.SIGINT])
...

def progress(...):
    try:
        signal.pthread_sigmask(signal.SIG_UNBLOCK, [signal.SIGINT])
    except KeyboardInterrupt:
        print('interrupted!')
        return 1
    finally:
        signal.pthread_sigmask(signal.SIG_BLOCK, [signal.SIGINT])


2. Using a pure try-expect-based method.

Regards,
Zhao

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Received on 2023-12-10