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Re: How to interpret CURLE_WEIRD_SERVER_REPLY?
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From: Patrick Monnerat via curl-library <curl-library_at_lists.haxx.se>
Date: Fri, 24 Oct 2025 01:08:55 +0200
On 10/23/25 9:12 PM, SherwoodP via curl-library wrote:
> This is my reply to Patrick Schlangen and Patrick Monnerat:
>>
>> It seems the code activates ther verbose output, but it has not been
>> posted. This is mandatory to have this to answer the initial question.
>>
>> Blindly, I can already say PLAIN mechanism is used instead of the Eudora
>> LOGIN choice, as the former is preferred by curl over the latter.
>>
>
> Attached is the verbose output from curl when I attempt to send an
> email using"secure mail keys" for authentication.
Thanks for the verbose output.
Be careful and change your SMTP password (key?): it has been published
by this post in base64 :-(
Plain login has been performed successfully.
Then curl tries to perform a (user) command because you neither tell to
upload something nor used mime posting. In the absence of real user
command, curl sends a VRFY command that is not supported by your server
--> CURL_WEIRD_SERVER_REPLY because "502 5.3.3 VRFY is not supported" is
not a curl expected reply.
Solution to your problem: add the following line to your program before
calling curl_easy_perform().
*code = curl_easy_setopt(curl, CURLOPT_UPLOAD, 1L);*
This should do the expected job.
Patrick
Date: Fri, 24 Oct 2025 01:08:55 +0200
On 10/23/25 9:12 PM, SherwoodP via curl-library wrote:
> This is my reply to Patrick Schlangen and Patrick Monnerat:
>>
>> It seems the code activates ther verbose output, but it has not been
>> posted. This is mandatory to have this to answer the initial question.
>>
>> Blindly, I can already say PLAIN mechanism is used instead of the Eudora
>> LOGIN choice, as the former is preferred by curl over the latter.
>>
>
> Attached is the verbose output from curl when I attempt to send an
> email using"secure mail keys" for authentication.
Thanks for the verbose output.
Be careful and change your SMTP password (key?): it has been published
by this post in base64 :-(
Plain login has been performed successfully.
Then curl tries to perform a (user) command because you neither tell to
upload something nor used mime posting. In the absence of real user
command, curl sends a VRFY command that is not supported by your server
--> CURL_WEIRD_SERVER_REPLY because "502 5.3.3 VRFY is not supported" is
not a curl expected reply.
Solution to your problem: add the following line to your program before
calling curl_easy_perform().
*code = curl_easy_setopt(curl, CURLOPT_UPLOAD, 1L);*
This should do the expected job.
Patrick
-- Unsubscribe: https://lists.haxx.se/mailman/listinfo/curl-library Etiquette: https://curl.se/mail/etiquette.htmlReceived on 2025-10-24