> However, as you can see there is another $ packet within the RTP payload. This messes up the remaining packet and packets to follow.

I think it is exactly like you say. That second $ is a valid byte of the payload. Only start interpreting interleave headers 1122 bytes after the first one (in this case).
Don't scan through the data... Or do I misunderstand?

Erik

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Received on 2018-04-11