First time exploring this very useful library and am having a simple
problem I'm unable to resolve, so would appreciate some help.

I'm doing a simple file download and have it working fine, except that
I have to 'hardcode' the local filename, because otherwise I seem
unable to have the download work. I'm basing this on the example
found at http://curl.haxx.se/libcurl/c/ftpget.html.

Rather than defining the local filename when declaring/initializing
the ftpfile parameter, as shown in the example:

    int main(void)
    {
      CURL *curl;
      CURLcode res;

      struct FtpFile ftpfile={
        "curl.tar.gz", /* name to store the file as if succesful */
        NULL
      };
    ...

I am setting the filename inside my program as follows:

    int main(void)
    {
      CURL *curl;
      CURLcode res;
      struct FtpFile ftpfile;

      ftpfile.filename = "curl.tar.gz";
      ftpfile.stream = NULL;

This works fine, but if I want to instead assign a variable value to
the filename, it doesn't work. I've tried various ways of getting a
variable string into the filename of the struct FtpFile and am
obviously missing something simple:

      char categoryName[32];
      int categoryNumber;
      char buffer[128];

      sprintf(buffer, "%s_%d.zip", categoryName, categoryNumber);
      ftpfile.filename = buffer;

or

    strcpy(ftpfile.filename, buffer)

Can someone please point out my error?

A related question is how do I download a file using it's existing
filename? The requested filename in the URL call allows me to use
variable names, so is there an option to simply save the file locally
using the same name without having to specify the name directly, which
is what's causing my problem above?

For example,
                sprintf(buffer, "ftp://%s/data/%d.zip", IPaddress,
categoryNumber);
                curl_easy_setopt(curl, CURLOPT_URL, buffer);

TIA
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Received on 2010-11-04