Hi all,
I use libcurl 7.24.0. I set curl in a thread like this:
        curl_easy_setopt(curl, CURLOPT_LOW_SPEED_LIMIT, 5);
        curl_easy_setopt(curl, CURLOPT_LOW_SPEED_TIME,30);
        curl_easy_setopt(curl, CURLOPT_CONNECTTIMEOUT, 15);
        curl_easy_setopt(curl, CURLOPT_NOSIGNAL, 1);
        curl_easy_setopt(curl, CURLOPT_TIMEOUT, 120);
and in another thread i use alarm() as below to do something ervery 60 seconds:
    ret = alarm(60);
    printf("alarm ret %d\n", ret);
    while(1)
    {
        if (sigwait(&sig_mask, &signo) != 0)
        {
            printf("Fail to sigwait\n");
            return NULL;
        }
        switch (signo)
        {
            case SIGALRM:
                ret = alarm(60);
            /* do somthing */
Sometimes, i got "curl_easy_perform() failed: Timeout was reached. " from libcurl, and submit data to server failed. But in fact, the sever get the data, i don't know why. Any suggestions? Thanks so much!:)

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Received on 2015-08-20