Dear LibCURL Support,

I want to play Internet video whose url is
"http://etele:Xdr56tFc@89.147.64.204:8888/RtlKlub". I have used curl_easy_setopt set CURLOPT_URL to http://89.147.64.204:8888/RtlKl, use
CURLOPT_USERPWD set the username and password as etele:Xdr56tFc,and used
"curl_easy_setopt(easyhandle, CURLOPT_HTTPAUTH, CURLAUTH_ANY)" set the
authentication method. As a result it can't play the video, and debug info
is "HTTP/1.0 403 Forbidden" . My platform is Linux .

 We shall appreciate any help you can give me. Please give me a example about the problem.Thank you very much!

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Received on 2011-12-16