> -----Original Message-----
> From: curl-library-bounces_at_cool.haxx.se
> [mailto:curl-library-bounces_at_cool.haxx.se] On Behalf Of HU Chengzhe
> Sent: Thursday, August 19, 2010 2:51 PM
> To: curl-library_at_cool.haxx.se
> Subject: About some FTP client functions by using libcurl
>
>
> Hello,
>
> I'm planing to implement a ftp client using libcurl.
> But when I try to implement some basic functions of ftp
> client, I encounter some problems.
>
>
> 1) getRootPath(), this function should return ftp server
> root path by absolute path format. my code as follow:
> int main(void){
> CURL *curl;
> CURLcode res;

  FILE *fHeader = NULL;

  if ((fHeader = fopen("./headerFile", "w")) == NULL)
  {
        printf("can't open header file");
        return -1;
  }

> curl_global_init(CURL_GLOBAL_DEFAULT);
>
> curl = curl_easy_init();
> if(curl) {
> curl_easy_setopt(curl, CURLOPT_URL,
> "ftp://135.252.234.82 <ftp://135.252.234.82> ");
> //set username for transfer
> curl_easy_setopt(curl, CURLOPT_USERNAME, "hello");
>
> //set password for transfer
> curl_easy_setopt(curl, CURLOPT_PASSWORD, "hello");
>
> struct curl_slist *headerlist = NULL;
> const char s[] = "PWD";
> headerlist = curl_slist_append(headerlist, s);
> curl_easy_setopt(curl, CURLOPT_POSTQUOTE, headerlist);

curl_easy_setopt(curl, CURLOPT_WRITEHEADER, fHeader);

> res = curl_easy_perform(curl);
>
> /* always cleanup */
> curl_easy_cleanup(curl);
> if(CURLE_OK != res) {
> fprintf(stderr, "curl told us %d\n", res);
> }
> }
> curl_global_cleanup();
> }
>
> expected result: print ftp server root path actual result:
> list all flie and directory information which are under ftp
> server root path, just like this:
> -r--r--r-- 1 oamops oamgroup 9539 Jul 9 2008 .alias_oam
> -rw------- 1 oamops oamgroup 1612 Aug 4 18:50 .bash_history
> -r--r--r-- 1 oamops oamgroup 7815 Feb 3 2010 .cshrc
> -r--r--r-- 1 oamops oamgroup 3268 Nov 19 2009 .cshrc.oamops
> -rw-r----- 1 oamops oamgroup 2309 Aug 18 14:33 .history
> -rw-r--r-- 1 oamops oamgroup 157 Jul 19 15:43 .login
> -rw------- 1 oamops oamgroup 30860 Jul 26 10:59 .lsof_zsups382
> -rw-r--r-- 1 oamops oamgroup 253 Jul 19 17:26 .profile
> .........
>
> so is there anyone can tell me why the result is like this?
> If this way can't work, please tell me how to implement the
> function of getRootPath().
>
> 2)getNodeType(), this function should return a node type, it
> may be file or directory. But until now, I have no idea about
> implementing it.
>
> Is there any API can be called? or other convenient way? The
> worsest way seems need a complicated string parse function to
> parse a string like this:
>
> -rw-r--r-- 1 oamops oamgroup 253 Jul 19 17:26 .profile
>
> 3)getPermission(), this function should return the access
> permission of a file or directory.
> The difficulty is same as problem 2). Is there convenient way
> to implement it?
-------------------------------------------------------------------
List admin: http://cool.haxx.se/list/listinfo/curl-library
Etiquette: http://curl.haxx.se/mail/etiquette.html
Received on 2010-08-19