On 12 May 2010 11:12, Simon Suchomel <suchomel_at_fi.muni.cz> wrote:
>  Dear members, could you please guide me how to pass a file to a destination server via libcurl in perl?
>
>  I am unable to pass a functional file handle, I'm trying to pass the handle via setopt with CURLOPT_POSTFIELDS option. I need to pass file as CGI parameter named FILE from the point of view of the target URL.
>
>  The same as on command line: curl -F 'FILE=@/home/myfile' https://someurl
>  It works fine via command line, thus I need to find alternative to the -F 'FILE=@/path' parameter via libcurl, but I'am unable to find it.
>
>  Thank you very much for any hint.

Try running:

$ curl -F 'FILE=@/home/myfile' https://someurl --libcurl postfields-example.c

and then look at the file called postfields-example.c that gets created.

-- 
Michael Wood <esiotrot_at_gmail.com>
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