Your first assumption is wrong:

CURLE_OK (zero) means that the option was set properly, non-zero means
an error occurred as <curl/curl.h> defines. See the libcurl-errors(3)
man page for the full list with descriptions.

RTM: http://curl.haxx.se/libcurl/c/curl_easy_setopt.html#RETURN

I didn't see anything wrong with the code, but try removing the
CURLOPT_VERBOSE.

Jason

Daniel Szczuka wrote:

> The following code is just a simple program I made to allow me to get
> the data from www.google.com yet once I execute it, all of the
> setopt's return 0, which I'm assuming means they failed, and when I
> don't have the "if(res != 0)" then the easy_perform call crashes. I'm
> fairly sure that I built everything correctly and I have it set to
> use the dll's since -lcurl for the static libraries wasn't working.
> I'm still new to this whole thing so I'm hoping that I just did
> something wrong, but with a program this simplified, I know it's not
> my code; I just can't see why the setopts aren't working.
>
> int main() {
> CURLcode res;
> curl_global_init(CURL_GLOBAL_ALL);
> CURL *curl = curl_easy_init();
> if(curl)
> {
> res = curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION,
> write_output);
> cout << endl << "setopt for CURLOPT_WRITEFUNCTION " << res <<
> endl;
> cout << endl << "setopt for CURLOPT_VERBOSE " <<
> curl_easy_setopt(curl, CURLOPT_VERBOSE, TRUE) << endl;
>
> curl_easy_setopt(curl, CURLOPT_URL, "www.google.com");
> cout << endl << "setopt for CURLOPT_URL " << res << endl;
> if(res != 0)
> {
> try {
> CURLcode success = curl_easy_perform(curl);
> cout << endl << endl << "CURLCode code " << success
> << endl;
> }
> catch(char * str)
> {
> cout << endl << endl << "Caught exception " << str <<
> endl;
> }
> }
> system("Pause");
> }
> }
>
Received on 2005-08-01