Daniel,

Thanks for the reply:
I found the "curl-and-php" mailing list this morning and have been
reviewing it. No real help yet.

I have been playing around with the code and found some resolution.
The original example snipit I tried caused an execution error.
The cause turned out to be this statement:
     $sendvars['upfile'] = "@$logo";

Removing the quotes around @$logo corrected the error.
     $sendvars['upfile'] = @$logo; <== This cleared the error

The following code now sends as multipart, but I still don't get my file
to go.

$url = "http://design/uyoffice/test/testrcv.php";
$logo = "logo.gif";

$sendvars['fname'] = "John";
$sendvars['lname'] = "Smith";
$sendvars['upfile'] = @$logo;

$ch=curl_init($url);
curl_setopt($ch,CURLOPT_HEADER,0);
curl_setopt($ch,CURLOPT_VERBOSE,0);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch,CURLOPT_POST,"1");
curl_setopt($ch,CURLOPT_POSTFIELDS,$sendvars);
$result = curl_exec($ch);

the content type shows as:
       multipart/form-data;
boundary=----------------------------3c0b91392537
so I am now geting multipart submittal.

My handler now has the following variable results.
$fname = John
$lname = Smith
$upfile = logo.gif <= should reflect the temp
file address
$upfile_name = null <= should reflect the file name
$upfile_type = null <= should reflect the mimetype

I am still stuck with a file name coming across, not the file itself.

Ed
ed_at_epsit.net

Daniel Stenberg wrote:

>On Tue, 9 Dec 2003, ed wrote:
>
>
>
>>Help!!! curl newbie in deep!!!
>>
>>
>
>No need to cross-post. Besides, you missed the most important mailing list for
>you: curl-and-php.
>
>
>
>>$sendvars['fname'] = "John";
>>$sendvars['lname'] = "Smith";
>>$sendvars['upfile'] = "@$logo";
>>$enc=array();
>>foreach($sendvars as $key=>$value)
>>$enc[]=urlencode($key)."=".urlencode($value);
>>curl_setopt($ch,CURLOPT_POSTFIELDS,implode("&",$enc));
>>
>>
>
>This looks very odd. Is this really the documented way to do multipart
>formposts using the PHP/CURL interface?
>
>
>

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Received on 2003-12-10