> Hello,
> I am using libcurl 7.8 version on WindowsNT, trying to post data to the
> server (java servlet)
> through following lines of code (after I get curl object from init):
> ...curl_easy_setopt(curl, CURLOPT_NOPROGRESS, 1);
> curl_easy_setopt(curl, CURLOPT_VERBOSE, 1);
> curl_easy_setopt(curl, CURLOPT_POST,1);
> curl_easy_setopt(curl, CURLOPT_URL, "UrlOfMyServlet "); (something
> like http://Site/Servlet)
> char* params = "reportName=resp&timeFrame=Month";
> curl_easy_setopt(curl,CURLOPT_POSTFIELDS, params);
> res = curl_easy_perform(curl);
>
> the output, that I get when verbose is set, is following:
> > POST /UrlOfMyServlet HTTP/1.1
> Host: mouse:8080
> Pragma: no-cache
> Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */*
> Content-Length: 31
> Content-Type: application/x-www-form-urlencoded
>
> reportName=resp&timeFrame=Month
> * Closing live connection (#0)
>
> Even though I do get to that servlet on the server's side, I do not see
> any of the parameters that I send with the post!!
> (site, that I am connecting to, is run through Tomcat and I send tomcat's
> port in url, if it matters)
> Can you please tell me, what am I doing wrong?
>
> Thank you.
> Nataly.
>
>

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Received on 2001-07-31