Hello,
I am answering my own question: It appears that the best thing to do was to
build libcurl from source.
Regards,

On Wed, Apr 2, 2008 at 10:01 AM, Arye <aryeh_at_bigfoot.com> wrote:

> Hello again,
> Is there any way I could make this work with version 7.12.1 of pycurl?
>
> It seems that there was not attribute FORM_FILE in module pycurl version
> 7.12.1.
> Or is there an other way I can do a multipart/form-data post with pycurl
> version 7.12.1 ?
>
>
> My problem is that upgrading to the current version of pycurl on Red Hat
> Enterprise Linux 4 is not so easy because of the many dependencies of
> libcurl.
>
> Any help would be greatly appreciated.
> Regards,
> Arye.
>
>
> On Wed, Nov 14, 2007 at 11:13 PM, Nathan E. Moore <nate_at_redtetrahedron.org>
> wrote:
>
> > --On Wednesday, November 14, 2007 6:41 PM +0100 Arye - GMail
> > <aryeh_at_bigfoot.com> wrote:
> >
> > > Hello all,
> > > I am new to the list so sorry for the stupid questions...
> > >
> > > I have no success in converting this PHP code to Python:
> > <snip>
> > > Parameters = {'rm':'importFileContr',
> > > 'rf':'importProduct',
> > > 'sl':merchant_serial,
> > >
> > 'FILENAME':'c:/webserver/htdocs/pp_files/pp_product.csv'}
> > ># Do not forget '@' before the file to be called
> > >
> > > dataupdate=urllib.urlencode(Parameters)
> > >
> >
> > Your PHP is doing a multipart/form-data post not a
> > application/x-www-form-urlencoded post. (at least according to the PHP
> > documentation. To do a multipart/form-data post from pycurl, you need
> > to
> > use the HTTPPOST option. It's usage from python is a little different
> > than
> > from c (or PHP) see
> > <
> > http://pycurl.cvs.sourceforge.net/*checkout*/pycurl/pycurl/tests/test_post2.py?revision=1.13&content-type=text%2Fplain
> > >
> > and
> > <http://curl.haxx.se/mail/curlpython-2007-03/0003.html>
> > for more details.
> >
> > Nathan E. Moore
> > _______________________________________________
> > http://cool.haxx.se/cgi-bin/mailman/listinfo/curl-and-python
> >
>
>

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Received on 2008-04-02