curl-and-python
Re: pycurl-7.15.4 error with vc71 (with patch)
Date: Tue, 27 Jun 2006 21:39:47 +0200
dang!
thanks, will commit fix asap.
regards,
- kjetil
On 6/26/06, K.S.Sreeram <sreeram_at_tachyontech.net> wrote:
> Hi All
>
> I faced a simple compilation error in line 1830 of pycurl.c,
> because a new variable of type (CurlShareObject *) is being declared in
> the middle of a block (which is not allowed in C).
>
> I used the attached trivial patch to fix it.
>
> Regards
> Sreeram
>
>
> diff -urN pycurl-7.15.4.orig\src\pycurl.c pycurl-7.15.4\src\pycurl.c
> --- pycurl-7.15.4.orig\src\pycurl.c Wed Jun 14 00:36:28 2006
> +++ pycurl-7.15.4\src\pycurl.c Mon Jun 26 23:59:25 2006
> @@ -1803,6 +1803,7 @@
> }
> /* handle the SHARE case */
> if (option == CURLOPT_SHARE) {
> + CurlShareObject *share;
> if (self->share == NULL && (obj == NULL || obj == Py_None)){
> Py_INCREF(Py_None);
> return Py_None;
> @@ -1812,7 +1813,7 @@
> PyErr_SetString(ErrorObject, "Curl object already sharing. Unshare first.");
> return NULL;
> }else{
> - CurlShareObject *share = self->share;
> + share = self->share;
> res = curl_easy_setopt(self->handle, CURLOPT_SHARE, NULL);
> if (res != CURLE_OK){
> CURLERROR_RETVAL();
> @@ -1827,7 +1828,7 @@
> PyErr_SetString(PyExc_TypeError, "invalid arguments to setopt");
> return NULL;
> }
> - CurlShareObject *share = (CurlShareObject*)obj;
> + share = (CurlShareObject*)obj;
> res = curl_easy_setopt(self->handle, CURLOPT_SHARE, share->share_handle);
> if (res != CURLE_OK) {
> CURLERROR_RETVAL();
>
>
> _______________________________________________
> http://cool.haxx.se/cgi-bin/mailman/listinfo/curl-and-python
>
>
>
>
_______________________________________________
http://cool.haxx.se/cgi-bin/mailman/listinfo/curl-and-python
Received on 2006-06-27