Hi Tedd,

It actually sounds like you're six steps down the road;
Have you tried this;

"curl -u " + userIdStr + ":" + pwStr + " --url " + url + "?what=1"

I don't think you want to use "-d" because that will force an HTTP POST-
and I thought you were adamant about forcing an HTTP GET- that could cause
the web server you're trying to communicate with to get confused.

KC

On 12/30/05, tedd <tedd_at_sperling.com> wrote:
>
> Hi Kevin:
>
> >Well, my HTTP protocol understanding is kind of old, but I believe
> >that you can just send the "hidden" vars as you would any other
> >var... In curl, this is done via the "-d" param
>
> How do you combine a curl -d and a curl -u together?
>
> The curl command needs to send user-id and password as well as hidden
> data.
>
> Currently, I am using:
>
> "curl -u " + userIdStr + ":" + pwStr + " --url " + url
>
> which works to get into the protected application. But now, I need to
> send it hidden data as well. Something like:
>
> "curl -d " + "what=1" + url
>
> but, with userid and password.
>
> Any ideas?
>
> tedd
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Received on 2005-12-31