Andrew Hazen
-----Original Message-----
From: Andrew Hazen [mailto:andrewhazen_at_jatech.ca]
Sent: Tuesday, March 12, 2002 3:54 PM
To: 'Pete James'
Subject: RE: parsing url of returned page
 
When I post to the external site, I include a return url – my page. The
external site returns data to my url, but as GET variables in the url
string, as well as a default html page layout. If I echo $result I get
their default page, which I don’t want. I just want to capture the
fields contained in the url string that is sent back to me and captured.
 
Andrew Hazen
-----Original Message-----
From: curl-and-php-admin_at_lists.sourceforge.net
[mailto:curl-and-php-admin_at_lists.sourceforge.net] On Behalf Of Pete
James
Sent: Tuesday, March 12, 2002 3:36 PM
To: Andrew Hazen
Cc: curl-and-php_at_lists.sourceforge.net
Subject: Re: parsing url of returned page
 
The $result returned from the curl operation is the same output from the
external page that you would see if you used your browser to go to there
instead of curl. You can return any type of data to $result, but I'm
not sure I understand what URL string you are talking about. Could you
clarify?
Pete.
Andrew Hazen wrote:
Hi,
I have used curl in php to post to an external page.RETURNTRANSFER =1 so
that I capture the result to $result.
The data I need is in this returned URL string. How do I parse it
without printing out the entirety of $result??
  
 

-- 
Pete James, Advanis