Hum. Ok. Thanks for your example.
I've put file in a php variable.
But I want, for example, get title of the page. (<title>_____</title>)
According to U, I can't use fopen, so I can't use fgets...
What can I do?

Amaury

 -----Message d'origine-----
De : curl-and-php-admin_at_lists.sourceforge.net
[mailto:curl-and-php-admin_at_lists.sourceforge.net] De la part deDaniel
Stenberg
Envoyé : mercredi 7 mars 2001 13:59
À : 'curl and php list'
Objet : Re: CURLOPT_POSTFIELDS

On Wed, 7 Mar 2001, Amaury JOB wrote:

> I want to read a page (https://secured_site.com/page.cgi?p1=x&p2=y) I can
> connect me and display this page, but I want to read the file with fopen
> function.

Why?

> But I can't put fopen(" page.cgi?p1=x&p2=y ", " r ")
> No " ? " in fopen function.

No, you can't do that even without the ?. fopen() is a PHP internal function
that has no connection with libcurl. You simply don't use fopen() to get
pages with curl. If you want to use fopen(), then you can't use curl.

> Can U give the syntaxe to do that?

There's a very simple example shown here:
http://curl.haxx.se/lxr/source/docs/examples/getpageinvar.php

... that returns a web page in a PHP variable. What else could you possibly
want?

--
  Daniel Stenberg -- curl project maintainer -- http://curl.haxx.se/
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