I am trying to get the HTTP response from a simple servlet. The trouble is:
the program blocks at curl_easy_perform, and does not come out of it even if
the servlet has completed.

I have a running test Java servlet (deployed on Tomcat), which returns a
response code of 200.

protected void doGet(HttpServletRequest request, HttpServletResponse
response) throws ServletException, IOException
{
                System.out.println("doget - start ");
                ....
                response.setStatus(200);
                System.out.println("doget - end ");
}
       

I am attempting to write a C program using libcurl, which will just get the
response header. I have implemented the callback using
CURLOPT_HEADERFUNCTION. Code snippet below. Obviously, there is some mistake
out here. I tried with some other HTTP clients (wfetch), and there the
program completes, and it gets the response code 200.

Code snippet:

char *hdrdata;

size_t WriteHeaderCallback(void *ptr, size_t size, size_t nmemb, void *data)
{
        size_t realsize = size * nmemb;
        hdrdata = (char *) malloc (realsize);
        memcpy(hdrdata, ptr, realsize);
        return realsize;
}

...
...
curl_easy_setopt(hCurl, CURLOPT_HEADERFUNCTION, WriteHeaderCallback);
curl_easy_setopt(hCurl, CURLOPT_WRITEHEADER, (void *)&hdrdata);
...
....

/* The program blocks at this perform function. The servlet starts and
completes but this does not go ahead.
    Other HTTP client completes, so there is no issue with the servlet.
*/

if (curl_easy_perform(hCurl) == CURLE_OK)
                printf("Perform Ok\n");
        else
        {
                printf("\tError from cURL: %s\n", curl_easy_strerror(res));
                return -1;
        }

Any guidance would be nice.

-bash-3.00$ curl --version
curl 7.19.0 (sparc-sun-solaris2.10) libcurl/7.19.0 OpenSSL/0.9.8h zlib/1.2.3
Protocols: dict http file https
Features: Debug IPv6 Largefile NTLM SSL libz

Thanks in advance.

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