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Use percent sign (%) as command line argument

From: dimitri petrov <>
Date: Mon, 29 Oct 2007 03:23:59 +0300


Is it possible to use the percent sign as a command line argument for curl? For example when I want to login on a webpage and there is a percent sign in my password (which is actually the case :-) ) then my command line would be something like this:

curl -u username:pass%word

Of course this won't work because the percent sign has a special meaning for the windows shell. But how can I escape it. I tried %% and also ^% but both didn't work.

Thanks for any help in advance!
Received on 2007-10-29