Hi,

Is it possible to use the percent sign as a command line argument for curl? For example when I want to login on a webpage and there is a percent sign in my password (which is actually the case :-) ) then my command line would be something like this:

curl -u username:pass%word http://mysite.com

Of course this won't work because the percent sign has a special meaning for the windows shell. But how can I escape it. I tried %% and also ^% but both didn't work.

Thanks for any help in advance!
Received on 2007-10-29